mohon bantuannya soal logaritma * 4 log (4x-1) + 4 log (2x-1) = 5 log (8x² - 6x - 1) * 4 log (x²+2x-14) = 7 log (x²+2x-14) * 4 log (4x-1) - 5 log (4x-1) = 5
Matematika
toei
Pertanyaan
mohon bantuannya soal logaritma
* 4 log (4x-1) + 4 log (2x-1) = 5 log (8x² - 6x - 1)
* 4 log (x²+2x-14) = 7 log (x²+2x-14)
* 4 log (4x-1) - 5 log (4x-1) = 5 log (2x-1) - 4 log (2x-1)
* 4 log (4x-1) + 4 log (2x-1) = 5 log (8x² - 6x - 1)
* 4 log (x²+2x-14) = 7 log (x²+2x-14)
* 4 log (4x-1) - 5 log (4x-1) = 5 log (2x-1) - 4 log (2x-1)
1 Jawaban
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1. Jawaban gracelaanabel
1. gak tau
2. x = 3, x = -5
3. x = 0, x =3/4
kayanya nomor 1 agak aneh soalnya. sorry klo salah, ya...