Jika ²log 3 = p dan ²log 7 = q ,maka 27log 42 adalah

^27 log 42
=²log 42 / ²log 27
=²log (2×3×7) / ²log 3³
=(²log 2 + ²log 3 + ² log 7) / 3 ²log 3
=(1+p+q)/3p

[tex] ^{27}log42 [/tex]=[tex] \frac{ ^{2}log42 }{ ^{2}log27 } [/tex]
=²log42=²log(2 x 3 x 7)=1+p+q
=²log27=²log3³=3 . ²log3=3.p=3p
maka [tex] \frac{ ^{2}log42 }{ ^{2}log27 } [/tex]=[tex] \frac{1+p+q}{3p} [/tex]






gunakan rumus =[tex] ^{a} [/tex]logb=[tex] \frac{loga}{logb} = \frac{ ^{c}loga }{ ^{c} logb} [/tex]