tolong dibantu saya akan berterima kasih sekali mohonnya bantuannya
Matematika
murtinsy
Pertanyaan
tolong dibantu saya akan berterima kasih sekali mohonnya bantuannya
1 Jawaban
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1. Jawaban Anonyme
Simak ya...
•
11^(x² - 2x - 5) = 1/121
11^(x² - 2x - 5) = 11^-2
x² - 2x - 5 = -2
(x - 3)(x + 1) = 0
x = 3 atau x = -1
•
5^(x² + 2x + 5) = 5^(-3x - 1)
x² + 2x + 5 = -3x - 1
(x + 2)(x + 3) = 0
x = -2 atau x = -3
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4^(x - 1) - 18 . 2^(x - 2) + 8 = 0
(2^x)²/4 - 18/4 . 2^x + 32/4 = 0
(2^x)² - 18 . 2^x + 32 = 0
(2^x - 2)(2^x - 16) = 0
2^x = 2 ---> x = 1
2^x = 16 ---> x = 4
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(x - 5)^(3x² + 5x - 3) = (x - 5)^(x² - 5x + 5)
x - 5 = 1 ---> x = 6
3x² + 5x + 3 = x² - 5x - 5
2x² + 10x + 8 = 0
x² + 5x + 4 = 0
(x + 1)(x + 4) = 0
x = -1 atau x = -4
•
(x - 1)^(x² - 7x + 10) = (2x - 3)^(x² - 7x + 10)
x² - 7x + 10 = 0
(x - 2)(x - 5) = 0
x = 2 atau x = 5
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(1/2)^(2x² + 3x) > (1/2)^2
2x² + 3x < 2
2x² + 3x - 2 < 0
(2x - 1)(x + 2) < 0
-2 < x < 1/2