Matematika

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tolong dibantu saya akan berterima kasih sekali mohonnya bantuannya
tolong dibantu saya akan berterima kasih sekali mohonnya bantuannya

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    11^(x² - 2x - 5) = 1/121
    11^(x² - 2x - 5) = 11^-2
    x² - 2x - 5 = -2
    (x - 3)(x + 1) = 0
    x = 3 atau x = -1


    5^(x² + 2x + 5) = 5^(-3x - 1)
    x² + 2x + 5 = -3x - 1
    (x + 2)(x + 3) = 0
    x = -2 atau x = -3


    4^(x - 1) - 18 . 2^(x - 2) + 8 = 0
    (2^x)²/4 - 18/4 . 2^x + 32/4 = 0
    (2^x)² - 18 . 2^x + 32 = 0
    (2^x - 2)(2^x - 16) = 0
    2^x = 2 ---> x = 1
    2^x = 16 ---> x = 4


    (x - 5)^(3x² + 5x - 3) = (x - 5)^(x² - 5x + 5)
    x - 5 = 1 ---> x = 6

    3x² + 5x + 3 = x² - 5x - 5
    2x² + 10x + 8 = 0
    x² + 5x + 4 = 0
    (x + 1)(x + 4) = 0
    x = -1 atau x = -4


    (x - 1)^(x² - 7x + 10) = (2x - 3)^(x² - 7x + 10)
    x² - 7x + 10 = 0
    (x - 2)(x - 5) = 0
    x = 2 atau x = 5


    (1/2)^(2x² + 3x) > (1/2)^2
    2x² + 3x < 2
    2x² + 3x - 2 < 0
    (2x - 1)(x + 2) < 0
    -2 < x < 1/2