Matematika

Pertanyaan

jika log 3 = 0.477 dan log 5=0.699. maka,log 22,5 adalah?

2 Jawaban

  • Log22,5 = log (5x4,5)
    = log 5 + log 4,5
    = log 5 + log (45/10)
    = log 5 + (log45-log10)
    = log 5 + log 45 - 1
    = log 5 + ( log(9x5) ) - 1
    = log 5 + ( log 9 + log 5 ) - 1
    = 2.log5 + log 3² - 1
    = 2 log 5 + 2.log 3 - 1
    = 2. 0,699 + 2.0,477 - 1
    = 1,398 + 0,954 - 1
    = 1,352


    Semoga bermanfaat
  • log 3 = 0,477
    log 5 = 0,699
    log 22,5 = ....??

    log 22,5 = log (225/10)
    log 22,5 = log ((5 × 5 × 3 × 3)/10)
    log 22,5 = log ((5^2 × 3^2)/10)
    log 22,5 = log 5^2 + log 3^2 - log 10
    log 22,5 = 2 log 5 + 2 log 3 - log 10
    log 22,5 = 2(0,699) + 2(0,477) - 1
    log 22,5 = 1,398 + 0,954 - 1
    log 22,5 = 2,352 - 1
    log 22,5 = 1,352

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