Matematika

Pertanyaan

Dua buah bangun di bawah ini sebangun hitunglah a panjang ef.hg.ad.dc b nilai x.y dan z

1 Jawaban

  • A) EF : AB = FG : BC
    EF : 20 = 28 : 35
    35.EF = 20 . 28
    35.EF = 560
    EF = 560/35
    EF = 16 cm
    HG = \sqrt{ EF^{2} - (FG - EH)^{2} }
    = \sqrt{ 16^{2} + 12^{2} }
    = \sqrt{256 + 144}
    = \sqrt{400}
    = 20 cm
    EH : AD = FG : BC
    16 : AD = 28 : 35
    28.AD = 16 . 35
    28.AD = 560
    AD = 560/28
    AD = 20 cm
    HG : DC = FG : BC
    20 : DC = 28 : 35
    28.DC = 35 . 20
    28.DC = 700
    DC = 700/28
    DC = 25 cm
    2B) X = 180° - 127°
    = 53°
    Y = 127°
    Z = X
    = 53°

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