Matematika

Pertanyaan

tolong bantu jawab, please!
tolong bantu jawab, please!

1 Jawaban

  • Persamaan Linier Tiga Variabel
    ..
    (1)
    x+y =  5
    y + z = 6
    2x + y + z = 2 --> 2 x + (y+z) = 2
    2x + (6) = 2
    2x = 2 - 6 = - 4
    x = -4/2 = -2

    x + y = 5 --> y = 5 - x
    y = 5 - (-2)
    y = 7

    y + z = 6 --> z = 6 - y
    z = 6 -7
    z = -1

    x + y + z = (-2) + (7) + (-1) = -3 + 7
    x+ y + z = 4

    (2)
    x + y + z = -3 --> (x+y) = -3 - z
    x - y = 7
    2x + 2y - z = 6  --> 2 (x+ y)  - z = 6
    2(-3-z) - z = 6
    -6 - 2z - z = 6
    -3z = 6 + 6= 12
    z = 12/-3
    z = -4

    x + y = -3 - z
    x + y = -3 -(-4) = -3 + 4
    x + y = 1
    .
    x + y = 1
    x - y = 7
    ......(+)...
    2x = 8
    x = 4
    .
    x + y = 1
    4 + y = 1
    y = 1 - 4
    y = - 3

    (x,y,z) = (4, -3, -4)