Tentukan integral dari 2xkuadrat per √(2xpangkat3-5)pangkat5

^ tanda pangkat

(2x² / √(2x³ - 5)^5) dx
= {(2x² / {(2x³-5)^5}^½} dx
= {(2x² / {2x³-5}^5/2} dx
= {(2x²) (2x³-5)^-5/2} dx
misalkan 2x³ - 5 = u
(6x²)dx = du
dx = du/6x²
ubah ke u

= {2x² u^-5/2} du/6x²
= (2x²/6x²) u^-52 du
= ⅓ u^-5/2 + C
= ⅓ (1 / (1-5/2)u^(1-5/2)+ C
= ⅓ (1/3/2)u^(3/2) + C
= ⅓(2/3)u^3/2 + C
=2u^3/2 + C
= 2√{(2x³ - 5)³}+ C
= 2(2x³ - 5)√(2x³ - 5) + C