1) suatu fungsi f(x) = 2x -3 , memiliki domain { x | 1 ≤ x < 5 , x ∈ bil.asli } tentukan : a) Range

f(x) = 2x - 3
Domain = {x | 1 ≤ x < 5, x ∈ bil. asli}
Domain = {1, 2, 3, 4}

Range:
f(1) = 2(1) - 3 = 2 - 3 = -1
f(2) = 2(2) - 3 = 4 - 3 = 1
f(3) = 2(3) - 3 = 6 - 3 = 3
f(4) = 2(4) - 3 = 8 - 3 = 5

Range = {-1, 1, 3, 5}

Jawab :

1) Domain = { 1 , 2 , 3 , 4 }

 A) x = 1
f(x) = 2x -3
f(1) = 2(1) - 3
= -1

B) x = 2 
f(x) = 2x -3 
f(2) = 2(2) - 3
= 1

c) x = 3
f(x) 2x - 3
f(3) = 2(3) - 3
= 6 - 3
= 3

D) x = 4
f(x) = 2x -3
f(4) = 2(4) - 3
= 8 - 3
= 5

Jadi Range = { -1 , 1 , 3 , 5 }