luas selimut kerucut jika tinggi dan jari jarinya masing masing 5 cm dan 12 cm adalah...cm² pakai cara ya kak

keterangan :
s = garis pelukis
t = tinggi
r = jari jari
^2 = kuadrat
Π = phi

s^2 = t^2 + r^2
s^2 = 5^2 + 12^2
s^2 = 25 + 144
s^2 = 169
s = √169
s = 13

L selimut kerucut
= Π × r × s
= 3,14 × 12 × 13
= 489,84 cm^2