Matematika

Pertanyaan

(spltv) 2y - 3z = -7, x + y = 1, 3x + 2z = 6

1 Jawaban

  • 2y - 3z = -7
     x + y = 1  .................... y = 1 -x
    3x + 2z = 6


    y = 1 -x substitusi ke 2y - 3z = -7
    2(1-x)  -3z =-7
    2 - 2x -3z =-7
    -2x-3z = -7-2
    -2x-3z = -9

    eliminasi
    -2x-3z = -9 dan 3x + 2z = 6

    -2x-3z = -9 ......(x3)
    3x + 2z = 6 ......(x2)
    maka
    -6x -9z = -27
    6x +4z =12
    ----------------- +
    -5z = -15
    z = -15/-5
    z = 3

    shg 2y -3z =-7
    2y -3(3) =-7
    2y -9 = -7
    2y = -7+9
    2y = 2
    y = 1

    x+y = 1
    x+1=1
    x = 1-1
    x =0

    jadi x= 0, y=1, z =3



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