harga bilangan kuantum yang mungkin untuk orbital: a. n = 3, l =1, m=2, s =+1/2 b. n = 4, l = 0, m=_1, s = _1/2.
Kimia
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Pertanyaan
harga bilangan kuantum yang mungkin untuk orbital: a. n = 3, l =1, m=2, s =+1/2 b. n = 4, l = 0, m=_1, s = _1/2. c. n = 3, l = 2, m = _1, s =+1/2. d. n =2, l =2, m =_1,s=1/2. e. n = 2, l =1, m =+3, s=+1/2
1 Jawaban
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1. Jawaban AiniLavoisier
a. n = 3, l =1, m=2, s =+1/2 (elektron terakhir = 3p3)
b. n = 4, l = 0, m=0, s = -1/2. (elektron terakhir = 4s2)
c. n = 3, l = 2, m = -1, s =+1/2. (elektron terakhir = 3d2)
d. n =3, l =2, m =-1,s=1/2. (elektron terakhir = 3d2)
e. n = 2, l =1, m =+3, s=+1/2 (elektron terakhir = 2p3)