Mohon bantuannya soal logaritma * 4 log (4x-1) + 4 log (2x-1) = 5 log (8x² - 6x - 1) * 4 log (x²+2x-14) = 7 log (x²+2x-14) * 4 log (4x-1) - 5 log (4x-1) = 5 log
Matematika
toei
Pertanyaan
Mohon bantuannya soal logaritma
* 4 log (4x-1) + 4 log (2x-1) = 5 log (8x² - 6x - 1)
* 4 log (x²+2x-14) = 7 log (x²+2x-14)
* 4 log (4x-1) - 5 log (4x-1) = 5 log (2x-1) - 4 log (2x-1)
di sertakan caranya yaaa
1 Jawaban
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1. Jawaban Muronu
* ^{4} log (4x-1) + ^{4} log (2x-1) = ^{5} log ( 8x^{2} - 6x + 1 )
^{4} log (4x-1)(2x-1) = ^{5} log ( 8x^{2} - 6x + 1 )
^{4} log ( 8x^{2} - 6x + 1 ) = ^{5} log ( 8^{2} - 6x + 1 )
^{4} log ( 8x^{2} - 6x + 1 )
^{5} log ( 8x^{2} - 6x + 1 )
^{5} log 4
* ^{4} log ( x^{2} +2x - 14 ) = ^{7} log ( x^{2} + 2x - 14 )
^{4} log ( x^{2} + 2x - 14 )
^{7} log ( x^{2} + 2x - 14 )
^{7} log 4
* ^{4} log (4x-1) - ^{5} log (4x-1) = ^{5} log (2x-1) - ^{4} log (2x-1)
^{4} log (4x-1) + ^{4} log (2x-1) = ^{5} log (2x-1) + ^{5} log (4x-1)
^{4} log (4x-1)(2x-1) = ^{5} log (2x-1)(4x-1)
^{4} log ( 8x^{2} - 6x + 1 ) = ^{5} log ( 8x^{2} - 6x + 1 )
^{4} log ( 8x^{2} - 6x + 1 )
^{5} log ( 8x^{2} - 6x + 1 )
^{5} log 4